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Find the kissing lengths of the sides of the triangle.

Find the kissing lengths of the sides of the triangle.-example-1

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Answer: The last option.

Explanation:

The triangle shown in the figure attached is a right triangle.

1. You can calculate the lenght a as following:


sin\alpha=(opposite)/(hypotenuse)


opposite=a\\hypotenuse=6in\\\alpha=30\°

Substitute values and solve for a. Then, you obtain:


sin(30\°)=(a)/(6in)\\a=6in*sin(30\°)\\a=3in

2. You can calculate the lenght b as following:


cos\alpha=(adjacent)/(hypotenuse)


adjacent=b\\hypotenuse=6in\\\alpha=30\°

Substitute values and solve for b. Then, you obtain:


cos(30\°)=(b)/(6in)\\b=6in*cos(30\°)


b=3√(3)in

User Dzmitry  Prakapenka
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