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In order for an infinite geometric series to have a sum, the common ration has to be greater than one.

True or false?

User Ajean
by
5.0k points

2 Answers

2 votes

Answer:

The statement is false.

Explanation:

The sum of a geometric progression is given by


s_n=(a(r^n-1))/(r-1)

For an infinite GP the sum is given by


s_\infty =(a)/(1-r)

This equation can only be used when the common ratio is less than 1.

Here the statement is in order for an infinite geometric series to have a sum, the common ration has to be greater than one. This statement is wrong because the sum equation can only be used when the common ratio is less than 1.

The statement is false.

User Tristian
by
4.8k points
5 votes

Answer:

FALSE

Explanation:

If the series has a finite sum, the common ratio is less than 1.

User Nick Robertson
by
4.5k points
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