here since string is attached with a mass of 2 kg
so here tension force in the rope is given as
![T = mg](https://img.qammunity.org/2020/formulas/physics/high-school/4wkg4np5nu7q4mvxe3f905xpzsukeh7wbj.png)
here we will have
![T = 2(9.8) = 19.6 N](https://img.qammunity.org/2020/formulas/physics/high-school/7mka01p0bjk37vfaqcoir9x8qi7vysc73b.png)
now we will have speed of wave given as
![v = \sqrt{(T)/(\mu)}](https://img.qammunity.org/2020/formulas/physics/high-school/9lff6q72slumjkyw4eqn0w6r1xtga10zuj.png)
here we will have
![v = \sqrt{(19.6)/(0.75* 10^(-2))}](https://img.qammunity.org/2020/formulas/physics/high-school/zdj91hd6vrr3fa23tcfndc7skipruh50h5.png)
![v = 16.33 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/jvj3nfbhojce06ixqbz5oa2aopn8abz5up.png)
now we know that frequency is given as
F = 100 Hz
now wavelength is given as
![\lambda = (v)/(F)](https://img.qammunity.org/2020/formulas/physics/high-school/rxs1eqdcskql17ot1198butrhxpn922187.png)
![\lambda = (16.33)/(100) = 0.16 m](https://img.qammunity.org/2020/formulas/physics/high-school/pbf8heqlsp66m6ttf4jy8d3y3dnqv3mw3j.png)
so wavelength will be 0.16 m