Question

Calculate the mass in grams of each of the followinga. 5.94 x 10^20 H2O2 moleculesb. 2.8 x 10^22 SO2 moleculesc. 4.5 x 10^25 O3 moleculesd. 9.85 x 10^19 CH4 molecules

Answer 1

`0.0335\ \text{g}`

`2.978\ \text{g}`

`3586.84\ \text{g}`

`0.0026\ \text{g}`

Step-by-step explanation:

Mass in grams is given by

`m=(nM)/(N_A)`

where

n = Number of molecules

`N_A` = Avogadro's number =
`6.022* 10^(23)\ \text{mol}^(-1)`

M = Molar mass of molecule

Molar mass of
`H_2O_2` = 34.0147 g/mol

`n=5.94* 10^(20)`

`m=(5.94* 10^(20)* 34.0147)/(6.022* 10^(23))\\\Rightarrow m=0.0335\ \text{g}`

Mass of
`H_2O_2=0.0335\ \text{g}`

Molar mass of
`SO_2` = 64.066 g/mol

`n=2.8* 10^(22)`

`m=(2.8* 10^(22)* 64.066)/(6.022* 10^(23))\\\Rightarrow m=2.978\ \text{g}`

Mass of
`SO_2=2.978\ \text{g}`

Molar mass of
`O_3` = 48 g/mol

`n=4.5* 10^(25)`

`m=(4.5* 10^(25)* 48)/(6.022* 10^(23))\\\Rightarrow m=3586.84\ \text{g}`

Mass of
`O_3=3586.84\ \text{g}`

Molar mass of
`CH_4` = 16.04 g/mol

`n= 9.85* 10^(19)`

`m=(9.85* 10^(19)* 16.04)/(6.022* 10^(23))\\\Rightarrow m=0.0026\ \text{g}`

Mass of
`CH_4=0.0026\ \text{g}`