Question

Evaluate b^2c^-1 for b=8 and c=-4

Answer 1

For this case we must evaluate the following expression:

`(b ^ 2) (c ^( -1))`

When
`b = 8` and
`c = -4`

By power properties we have to:

`a ^ {-1} = \frac {1} {a ^ 1} = \frac {1} {a}`

Then, we can rewrite the expression as:

`(b ^ 2) * (\frac {1} {c}) = \frac {b ^ 2} {c}`

Substituting the values we have:

`\frac {8 ^ 2} {- 4} = \frac {64} {- 4} = - 16`

Answer:

-16

Answer 2

-16

Explanation:

b^2 *c^-1

Let b=8 and c=-4

(8)^2 * (-4)^-1

The negative exponent goes to the denominator

64 * 1/(-4)^1

64 *1/(-4)

-16