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What is the point-slope form of a line with slope 4/5 that contains the point (-2, 1)?​

User Penney
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1 Answer

3 votes

Answer:


y-1 = (4)/(3)(x+2)

Explanation:

To write the equation of the line, use the formula for point slope
y-y_1=m(x-x_1). Substitute m = 4/5 and the point (-2,1).


y-y_1 = m(x-x_1)\\y-1 = (4)/(3)(x--2)\\y-1 = (4)/(3)(x+2)

User Ajay Dabas
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