Answer: The pressure that the gas exert at high temperature is 9.63 atm
Step-by-step explanation:
To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
![(P_1)/(T_1)=(P_2)/(T_2)](https://img.qammunity.org/2020/formulas/chemistry/high-school/rk4xg6yrmhego89fatld1qeuepq135sjo6.png)
where,
are the initial pressure and temperature of the gas.
are the final pressure and temperature of the gas.
We are given:
![P_1=5.0atm\\T_1=76^oC=[76+273]K=349K\\P_2=?\\T_2=399^oC=[273+399]K=672K](https://img.qammunity.org/2020/formulas/chemistry/high-school/sex2m0kn67tr122xybfkgb2l4m33kp8uli.png)
Putting values in above equation, we get:
![(5.0atm)/(349K)=(P_2)/(672K)\\\\P_2=9.63atm](https://img.qammunity.org/2020/formulas/chemistry/high-school/lcqkkg6rv0t6t3mc7g7z7cuuy1kfpv8wg6.png)
Hence, the pressure that the gas exert at high temperature is 9.63 atm