For this case, we have to give two points of the form:
![(x_ {1}, y_ {1}) and (x_ {2}, y_ {2}})](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4oc573r36c4eeya4ghgsn0l38lpfdkzenv.png)
The formula of the midpoint is given by:
![(\frac {x_ {1} + x {2}} {2}, \frac {y_ {1} + y_ {2}} {2})](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lvpucg2sgpp0e8unrs6nk1hbxzggpd4wle.png)
So, be:
(10,3) and (-2, -5)
Substituting in the formula we have:
![(\frac {10 + (- 2)} {2}, \frac {3 + (- 5)} {2}) =\\(\frac {10-2} {2}, \frac {3-5} {2}) =](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y5qsvmxenezmdjmwwpc4lnrgxjebyngs79.png)
Different signs are subtracted and the greater sign is placed:
![(\frac {8} {2}, \frac {-2} {2}) =](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5du0dx03kgczxs8g95bnhpq7hksdauaify.png)
(4, -1)
Thus, the midpoint is (4, -1)
Answer:
(4, -1)