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What is the slope of the line that contains the points (-23, -16) and (13, -16)?What is the slope of the line that contains the points (-2, 1) and (0, -3)?

2 Answers

4 votes

Answer:

1. Slope is 0

2. Slope is -2

Explanation:

1. (-23,-16) and (13,-16)

Slope formula


\displaystyle (y_2-y_1)/(x_2-x_1)=(rise)/(run)


\displaystyle ((-16)-(-16))/(13-(-23))=(0)/(36)=0

The slope is 0.

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2. (-2,1) and (0,-3)


\displaystyle ((-3)-1)/(0-(-2))=(-4)/(2)=-2

The slope is -2.

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User Sean Lintern
by
7.9k points
4 votes

Answer:

  1. the slope is 0 (zero)
  2. the slope is -2

Explanation:

1. Slope is the ratio of (change in y) to (change in x). Here there is no change in y. (y is constant at -16) So, the slope is zero (0).

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2. The change in y is (-3 -1) = -4. The change in x is (0 -(-2)) = 2. The ratio of change in y to change in x is ...

slope = (change in y)/(change in x) = -4/2 = -2

User Knelis
by
9.0k points

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