What is the slope of the line that contains the points (-23, -16) and (13, -16)?What is the slope of the line that contains the points (-2, 1) and (0, -3)?

Question

asked Jan 12, 2020 173k views

2 Answers

Sean Lintern · Answer 1 · 2020-01-12T22:46:26+0000

Answer:

1. Slope is 0

2. Slope is -2

Explanation:

1. (-23,-16) and (13,-16)

Slope formula

$\displaystyle (y_2-y_1)/(x_2-x_1)=(rise)/(run)$

$\displaystyle ((-16)-(-16))/(13-(-23))=(0)/(36)=0$

The slope is 0.

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2. (-2,1) and (0,-3)

$\displaystyle ((-3)-1)/(0-(-2))=(-4)/(2)=-2$

The slope is -2.

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Knelis · Answer 2 · 2020-01-16T02:10:09+0000

Answer:

Explanation:

1. Slope is the ratio of (change in y) to (change in x). Here there is no change in y. (y is constant at -16) So, the slope is zero (0).

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2. The change in y is (-3 -1) = -4. The change in x is (0 -(-2)) = 2. The ratio of change in y to change in x is ...

slope = (change in y)/(change in x) = -4/2 = -2