Question

the verticales of triangle XYZ are X(-3,-6),Y(21,-6),and Z(21,4). What is the perimeter of the triangle​

Answer 1

P = 60

Explanation:

The formula of a distance between two points:

`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

X(-3, -6), Y(21, -6). Substitute:

`XY=√(21-(-3))^2+(-6-(-6))^2)=√(24^2+0^2)=√(24^2)=24`

X(-3, -6), Z(21, 4). Substitute:

`XZ=√((21-(-3))^2+(4-(-6))^2)=√(24^2+10^2)=√(576+100)=√(676)=26`

Y(21, -6), Z(21, 4). Substitute:

`YZ=√((21-21)^2+(4-(-6))^2)=√(0^2+10^2)=√(10^2)=10`

The perimeter of the triangle XYZ:

`P_(\triangle XYZ)=XY+XZ+YZ`

Substitute:

`P_(\triangle XYZ)=24+26+10=60`