Answer:
The system of equation that is represented is:
![y=x^2+6x+7\\\\x+y=1](https://img.qammunity.org/2020/formulas/mathematics/high-school/2f0bdrey33wczel69m2rkwiu4h9rkkkcy0.png)
Explanation:
It is given that:
a line is graphed through points negative 6 comma 7 and negative 1 comma 2.
i.e. a line passes through (-6,7) and (-1,2).
The equation of line passing through (a,b) and (c,d) is given by:
![y-b=(d-b)/(c-a)* (x-a)](https://img.qammunity.org/2020/formulas/mathematics/high-school/gk6ki7q05s11urh9ol9jvxbkgrcoig98bq.png)
Here (a,b)=(-6,7) and (c,d)= (-1,2).
Hence equation of line is:
![y-7=(2-7)/(-1+6)* (x-(-6))\\\\y-7=(-5)/(5)* (x+6)\\\\y-7=-1(x+6)\\\\y-7=-x-6\\\\x+y=-6+7\\\\x+y=1](https://img.qammunity.org/2020/formulas/mathematics/high-school/9v3nim8rvjmoayiahev7wg5t8x9luaiqzl.png)
Hence, the system of equation that satisfies these two points are:
![y=x^2+6x+7\\\\x+y=1](https://img.qammunity.org/2020/formulas/mathematics/high-school/2f0bdrey33wczel69m2rkwiu4h9rkkkcy0.png)
( As in all the other options the equation of line i.e. second equation does not passes through the given points )