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The sum of two numbers is 50. Two times the smaller number exceeds the larger number by 31. Find the numbers.

1 Answer

4 votes

Answer:

The smaller number is 23, the larger number is 27

Explanation:

Let x represent the smaller number, and let y represent the larger number, we can set up two equations from the given information.

"The sum of two numbers is 50" becomes x + y = 50

and

"Two times the smaller number exceeds the larger number by 31" becomes

2x = y + 31 (twice the smaller number is 31 more than the larger number)

so we have

x + y = 50

2x = y + 31

We will use substitution method to solve this system of equations

Step 1: Solve the second equation for 'y'

2x - 31 = y (subtract 31 from both sides to isolate 'y'), this can be rewritten as

y = 2x - 31

now plug that into the first equation and solve...

x + (2x - 31) = 50 (y becomes 2x - 31)

x + 2x - 31 = 50

3x = 81

x = 27

Since x = 27, y = 23

User Shahzad Fateh Ali
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