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A line has a slope of 2 and passes through the point (-3, -6) . What is its equation in slope -intercept form?

User Cobie
by
7.2k points

2 Answers

4 votes

Answer:

y = 2x

Explanation:

From question statement, we observe that

Slope and a point is given .We have to find the slope-intercept form of line.

Slope = 2 and (x,y) = (-3,-6)

y = mx+c eq(1)

is slope-intercept form of line where m is slope and c is y-intercept.

Putting given values in eq(1) , we have

-6 = (2)(-3)+c

-6 = -6+c

c = 0

Hence, y-intercept iszer0.

Putting the value of y-intercept and slope in eq(1), we have

y = (2)x+(0)

y = 2x is slope intercept form of line whose slope is 2 and passes through the point (-3,-6).

User Rizwan Saleem
by
7.8k points
6 votes

Answer:

Explanation:

The general equation of the slope intercept is y = mx + b.

Givens

m = 2

point: -3, - 6

Solution

Find the slope first

y = mx + b

y = 2x + b

Now use the fact that

  • y = - 6
  • x = - 3

-6 = 2*(-3) + b So you are solving for b

-6 = - 6 + b Add 6 to both sides.

-6 + 6 = -6+6 + b

b = 0

Final Answer

y = 2x

User Yosmar
by
8.0k points