For this case we have to, so that both runners finish at the same time, Dave must also reach 88 seconds.
![Dave\ runs\ to\ \frac {440} {55} = 8\ yards\ per\ second\\Jack\ runs\ to\ \frac {440} {88} = 5\ yards\ per\ second](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qfphm2a05xil3cpr34rdy7uodtxxl3c6hz.png)
With respect to the times we have:
![88-55 = 33](https://img.qammunity.org/2020/formulas/mathematics/middle-school/unb2sj6jjnqsnjnep1ad377hi45pk3psn2.png)
Dave must have a 33-second disadvantage.
This means that in those 33 seconds of difference Jack runs:
![5 * 33 = 165 \ yards](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6agi3rh8uo4x991umny26xkmakfcqr0abn.png)
So, Dave must lose 165 yards to get to Jack
Answer:
165