Hello from MrBillDoesMath!
Answer:
12/55
Discussion:
Start by simplifying the numerator:
( 3/(5b) - 2/(5b)) / ( 1/(4b) + 2/(3b) ) = => as 3/(5b)- 2/(5b) = 1/(5b)
(1/(5b) / (1/(4b) + 2/(3b) ) = => multiply num., denom. by "b"
(b * 1/(5b)) / ( b/(4b) +2b/(3b)) = => as b/b = 1
(1/5) / (1/4 + 2/3) = => 1/4 = 3/12; 2/3 = 8/12
(1/5)/ ( 3/12 + 8/12) =
(1/5)/ ( 11/12) = => 1/ (11/12) = 12/11
(1/5) 12/11 =
12/55
Thank you,
MrB