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What the vertex and AOS if the equation is y=(x-2)^2-2
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What the vertex and AOS if the equation is y=(x-2)^2-2

User MaRuf
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1 Answer

1 vote

Answer:

See below.

Explanation:

For y = a(x - b)^2 + c , the vertex is at (b, c) and the axis of symmetry is x = b.

So for y = (x-2)^2 - 2,

the vertex is (2, -2) and the axis of symmetry is x = 2.

User Hardy Mathew
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