Question

Someone please help me!

Answer 1

A.
`x \leq -16`

B. b > 11

C.
`c \leq -13`

D.
`x \geq -9`

Explanation:

Given the following algebraic expression;

A.
`\frac {3x}{4} \leq 12`

We would simplify the equation by multiplying all through by 4;

`4 * \frac {-3x}{4} \leq 12 * 4`

`-3x \leq 48`

Divide both sides by -3;

`x \leq -16`

B. 5b - 28 > 27

Rearranging the equation, we have;

5b > 27 + 28

5b > 55

Divide both sides by 5

b > 11

C.
`13c \leq -169`

Divide both sides by 13

`c \leq -13`

D.
`3x - 7 \geq 4x + 2`

Collecting like terms, we have;

`3x - 4x \geq 2 + 7`

`-x \geq 9`

Divide both sides by -1

`x \geq -9`