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The function

P(x)=
x
3
−2
x
2
P(x)=x3−2x2
, is dilated by the function
I(x)=P(4x)
I(x)=P(4x)
.
Which function rule represents
I(x)
I(x)
?

I(x)=4
x
3
−8
x
2
I(x)=4x3−8x2

I(x)=64
x
3
−2
x
2
I(x)=64x3−2x2

I(x)=4
x
3
−2
x
2
I(x)=4x3−2x2

I(x)=64
x
3
−32
x
2
I(x)=64x3−32x2

2 Answers

2 votes

Answer: I(x) is 64x³ - 32x²

Explanation:

We are given the function P(x)=x³−2x².

I(x) is given P(4x).

This means to get I(x), we replace x in the function P(x) to be 4x.

Therefore:

I(x) = P(4x) = (4x)³−2(4x)²

I(x) = P(4x) = 64x³ - 2(16x²)

I(x) = 64x³ - 32x²

User KerrM
by
5.6k points
4 votes

is this multiple questions??????????dont get what your asking

User Sasha Grey
by
5.9k points