Answer:
Option B is correct.
The domain of the function h(x) is:
![\x](https://img.qammunity.org/2020/formulas/mathematics/high-school/3r86co0kcgsf4aumxlknugzihzjkdvyulr.png)
Explanation:
Domain states that the complete set of all the possible values of the independent variable where function is defined.
Given the function:
![h(x) = (9x)/(x(x^2-36))](https://img.qammunity.org/2020/formulas/mathematics/high-school/i2tm7wdsymeae38v7lf1az1dxjdpi2ha8l.png)
To find the excluded value in the domain of the function.
equate the denominator to 0 and solve for x.
i.e
![x(x^2-36) = 0](https://img.qammunity.org/2020/formulas/mathematics/high-school/raup4dc3v1qaw1kt5v986mo3ex5wsm7u5w.png)
⇒x = 0 and
![x^2-36 = 0](https://img.qammunity.org/2020/formulas/mathematics/high-school/e9nyqz0q4nl9olx7fjb0bazf6l5gzpd2cd.png)
⇒x = 0 and
![x^2 = 36](https://img.qammunity.org/2020/formulas/mathematics/high-school/acxwbhhkk0318crw8vgpjwrgv1ozcfjmhc.png)
or
x = 0 and
![x = \pm 6](https://img.qammunity.org/2020/formulas/mathematics/high-school/uto3rqscv4v2hvk1u8jr1v53wce747zsj3.png)
So, the domain of the function h(x) is the set of all real number except x = 0 and
![x = \pm 6](https://img.qammunity.org/2020/formulas/mathematics/high-school/uto3rqscv4v2hvk1u8jr1v53wce747zsj3.png)
Therefore, the domain of the function h(x) is:
![\x](https://img.qammunity.org/2020/formulas/mathematics/high-school/3r86co0kcgsf4aumxlknugzihzjkdvyulr.png)