Factor 5x^2 + 19x - 4

Question

asked Oct 23, 2020 61.2k views

1 Answer

Ben Marini · Answer 1 · 2020-10-28T13:04:39+0000

Answer:

hello : 5x² + 19x - 4 =(x+4)(5x - 1)

Explanation:

5x² + 19x - 4

calculate Δ = b²- 4ac .... a = 5 b = 19 c = - 4

Δ = 19²- 4(5)(-4)= 361+80 = 441 = 21²

x1 = (-19 -21)/10 x2 = (-19+21)/10

x1 = -40/10= - 4 x2 = 2/10 = 1/5

note : ax²+bx +c = a(x - x1 ) ( x -x2) ........ a ≠0

5x² + 19x - 4 = 5 ( x +4)(x -1/5)

5x² + 19x - 4 =(x+4)(5x - 1)