Hello!
The answer is: There are 9 packets of 10-battery packets.
Why?
Let's make the calculations:
Let y b the 6-battery packet and z be the 10-battery packet.
We must construct the following to equations using the statement information: There is a stock of 25 packets and there is a total of 186 batteries formed by 6-battery packets and 10-battery packers
So, the first equation will be:
![y + z = 25](https://img.qammunity.org/2020/formulas/mathematics/high-school/z3rq3nut8cymfj57e1s4xus8sxkha3ksb1.png)
The second equation will be:
![6y+10z=186](https://img.qammunity.org/2020/formulas/mathematics/high-school/q0wj37mkawxv1dq6lnt3x29mvrnicowli6.png)
From the first equation we have:
![y=25-z](https://img.qammunity.org/2020/formulas/mathematics/high-school/uwtx43b8hs2kmo1w628f3rreh35tv0pt6z.png)
Substituting y in the second equation we have:
![6(25-z)+10z=186\\6(25-z)=186-10z\\150-6z=186-10z\\10z-6z=186-150\\4z=36\\z=(36)/(4)=9](https://img.qammunity.org/2020/formulas/mathematics/high-school/n0sjl0cd6k4see24q26h73no40qhuf9puw.png)
So, there are 9 packets of 10-battery packets.
By substituting z in the first equation we will know the number of 6-battery packets in stock
![y=25-9=16](https://img.qammunity.org/2020/formulas/mathematics/high-school/q3y8fzb6lmujqb079cctjji4dl42ns16v7.png)
So, there are 16 packets of 6-battery packets.
Have a nice day!