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What are the roots of this quadratic equation? 2x2 5x = x2 7x 35

User Zelix
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1 Answer

2 votes

Answer:

x=-5, x=7

Explanation:

We have the quadratic equations,


2x^2+5x=x^2+7x+35

We can rewrite this equation as


2x^2-x^2+5x-7x-35=0\\\\x^2-2x-35=0

We can solve for x using AC method.

AC = -35

B = -2

The factor pairs of 35 are

1×35, 7×5

Among these two, when we subtract 7 form 5, we get the middle term -2

Hence, -2x=-7x+5x


x^2-7x+5x-35=0\\\\\text{Take GCF}\\\\x(x-7)+5(x-7)=0\\\\\text{Factor out the common terms}\\\\(x-7)(x+5)=0\\\\x=-5,7

Thus, the roots are -5 and 7

User Noemi
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