Answer:
Kurt is standing 24.03 ft. from the base of the pole
Explanation:
Refer the attached figure .
Height of the pole = AB = 40 ft.
Since the bird is sitting on the top of the pole.
So, the angle of elevation from the ground where Kurt is standing to the bird = ∠ACB = 59°
We are required to find how far is Kurt standing from the base of the pole i.e. BC
So, we will use trigonometric ratio:





Thus BC = 24.03 ft.
Hence, Kurt is standing 24.03 ft. from the base of the pole