Answer:
Kurt is standing 24.03 ft. from the base of the pole
Explanation:
Refer the attached figure .
Height of the pole = AB = 40 ft.
Since the bird is sitting on the top of the pole.
So, the angle of elevation from the ground where Kurt is standing to the bird = ∠ACB = 59°
We are required to find how far is Kurt standing from the base of the pole i.e. BC
So, we will use trigonometric ratio:
![tan\theta = (Perpendicular)/(Base)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ql007qnp16yb1h9w49ei9vzkh1kcb5cvd3.png)
![tan59^(\circ)= (AB)/(BC)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ys256dlxvvv6trt5g4q9980e64lm5kvz8a.png)
![1.664= (40)/(BC)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/15ymbfs2mreep7c8hiyty18h868vcnk914.png)
![BC= (40)/(1.664)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xidhsphc24z8v26hd82lgqvs2b6f2p706p.png)
![BC=24.03](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v0ev6ula1kjderdlhlq8mn5pbl3m75yj8v.png)
Thus BC = 24.03 ft.
Hence, Kurt is standing 24.03 ft. from the base of the pole