Question

A basketball player can jump upwards with a velocity of 3m/s. How long is she in the air before coming back to the ground? I need the info with the units.

Answer 1

In this problem, we have an initial velocity
`v_(i)=3m/s` jump upwards (opposite direction to gravity) with the acceleration due to gravity
`g=-9.8m/s^2` , finally the player will reach to final velocity in the air
`v_(f)`

Using the equation of motion, the third equation states that:

`v_(f)^(2) =v_(i) ^(2)+2gh`

where h is the height , the distance which the player reach in air

Thus

`0^(2) =3 ^(2)+2*(-9.8)*h`

`h=(3^2)/(2*9.8)= (9)/(19.6)= 0.459m`