Question

PLEASE HELP!! A.S.A.P!!

The Pythagorean Theorem,
Right triangles Trigonometry

What is the value of X? Leave your answer in simplest Radical form

A.)

`2√(5)`

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B.)

`√(6)`

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C.)

`√(10)`


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D.)

`5√(2)`

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Answer 1

`\large\boxed{A.)\ 2\sqrt5}`

Explanation:

The Pythagorean theorem:

`leg^2+leg^2=hypotenuse^2`

We have

`\leg=2\\leg=4\\hypotenuse=x`

Substitute:

`x^2=2^2+4^2\\\\x^2=4+16\\\\x^2=20\to x=√(20)\\\\x=√(4\cdot5)\\\\x=\sqrt4\cdot\sqrt5\\\\x=2\sqrt5`