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The population of Nowhere, USA was estimated to be 886,000 in 2004, with an expected increase of 4% per year. At the percent of increase given, what was the expected population in 2005? Round your answer to the nearest whole number.

User Volkerschulz
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1 Answer

10 votes
10 votes

Answer:

y=886000(1.04)^t

t=1 year so answer is 886000*1.04 = 921440

User Yetunde
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