Question

Your last bag of Halloween candy contains 3 fruit candies, 2 chocolates, 5 caramels and 6 sour chews. If you pick a candy at random, what is the probability it will be caramel or chocolate?

Answer 1

Answer: Probability of getting caramel or chocolate is
`(7)/(16)`

Explanation:

Since we have given that

Number of fruit candies = 3

Number of chocolates = 2

Number of caramels = 5

Number of sour chews = 6

Total number of items is given by

`3+2+5+6\\\\=16`

Probability of getting caramel or chocolate is given by

`P(Caramel)+P(Chocolate)\\\\=(5)/(16)+(2)/(16)\\\\=(7)/(16)`

Hence, Probability of getting caramel or chocolate is
`(7)/(16)`

Answer 2

`(7)/(16)`

Explanation:

Halloween candy contains 3 fruit candies, 2 chocolates, 5 caramels and 6 sour chews

So, total candies = 3 fruit candies+2 chocolates+5 caramels + 6 sour chews

= 16

Thus total no. of candies = 16

Probability of occurring an event =
`\frac{\text{Favorable outcomes}}{\text{Total outcomes}}`

To find the probability of getting caramel or chocolate :

Favorable events : 5 caramels + 2 chocolates = 7

Total events = Total candies = 16

So, probability of getting caramel or chocolate:

=
`(7)/(16)`

Hence ,The probability of getting caramel or chocolate is
`(7)/(16)`