Question

(this is a rhombus btw) for what value of x is the figure the given special parallelogram? HELP PLS, show work.

Answer 1

x = 2 or 3

Explanation:

Diagonal of a rhombus bisects the vertex angles. So,

`x^(2) =5x-6`

`=> x^(2) -5x + 6 = 0`

Lets factorise the eqn.

`=> x^(2) - 2x - 3x + 6 = 0`

`=> x (x - 2) -3(x-2)`

`=> (x-2)(x-3) = 0`

Here x will have 2 values.

1)
`x-2=0`

`=> x =2`

2)
`x - 3 = 0`

`=> x = 3`