Answer:
The correct option is B.
Explanation:
From the given graph it is clear that the maximum value of the function is 2 at x=0, so it a cosine function.
The general form of a cosine function is
.... (1)
Where, a is amplitude, 2π/b is period, c is phase shift and d is midline.
Since maximum value is 2 and minimum value is 0, so
![Amplitude=a=(2-0)/(2)=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ecl1n0fqxm8zk32h9s6xws9hcivndaqm69.png)
![Midline=b=(2+0)/(2)=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/icskj84imcp8hq08x4tppleeajomim20lu.png)
![Period=2\pi\Rightarrow b=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6hwhmjpcelfot3lw6j3pn1hf6m3k6rxwh2.png)
Since maximum value is at x=0, therefore the phase shift is c=0.
Put these values in equation 1.
![y=1\cos(1x+0)+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wnfx7jzvfueydfwwrz8k2b7anpz3fshyjd.png)
![y=\cos(x)+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8g3viuyoyean54q61rvjurkadeqo2maxra.png)
Therefore the correct option is B.