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What is the equation of the graph below? A graph shows a parabola that opens down and crosses the x axis near one and a half and four and a half. (5 points) y = − (x + 2)2 + 2 y = − (x − 3)2 + 2 y = (x − 2)2 + 2 y = (x + 3)2 + 2

User Blagerweij
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1 Answer

1 vote

Answer:

y = -(x-3)² +2

Explanation:

The axis of symmetry is halfway between the zeros, so is about ...

(1.5 + 4.5)/2 = 3

This is the x-coordinate of the vertex. The only equation having a vertex with that x-coordinate is the answer shown above.

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The equation of a parabola with vertex (h, k) is ...

y = a(x -h)² +k

If the parabola opens downward and has real roots, the value of "a" will be negative and the value of "k" will be positive.

What is the equation of the graph below? A graph shows a parabola that opens down-example-1
User Harun ERGUL
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