Question

If 10g of sodium react with an unlimited amount of chlorine how much sodium chloride will get produced?

Answer 1

Answer: Amount of sodium chloride produced is 25.43 grams.

Step-by-step explanation:

To calculate the moles:

`\text{Number of moles}=\frac{\text{Given mass}}{\textMolar mass}}`

Given: Mass of sodium = 10 g

Molar mass of sodium = 23g/mol

`\text{Moles of sodium}=(10g)/(23g/mol)=0.4347mol`

The balanced equation is:

`2Na+Cl_2\rightarrow 2NaCl`

By Stoichiometry of the reaction,

2 moles of sodium produces 2 moles of sodium chloride

So, 0.4347 moles of sodium will produce =
`(2)/(2)* 0.4347=0.4347mol` of sodium chloride.

Molar mass of sodium chloride = 58.5 g/mol

Putting values in equation 1, we get:

`0.4347mol=\frac{\text{Mass of NaCl}}{58.5g/mol}=25.43g`

Hence, amount of sodium chloride produced is 25.43 grams.