Answer:
Explanation:
Given that the range of f(x) = ^mx and the range of g(x) = m ^ x are the same
i.e. a^mx and m^x will have the same range.
If m =1, then we have second function as 1 and hence cannot be correct
If m <0 and a>0 then I function will be positive while second function negative. So range cannot be equal
If m is any real number then same argument for negative number makes this false.
If m>0, and a>0 then a^mx and also m^x will be positive and hence range is R+ including 0