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3 votes
Solve the system of equations algebraically.

3x-3y=6
6x-7y=8

a.(5,5)
b. many solutions
c. no solution
d. (6,4)

User Yaman
by
8.1k points

2 Answers

3 votes

Answer:

Choice d is correct answer.

Explanation:

We have given two equation.

3x-3y = 6 eq(1)

6x-7y = 8 eq(2)

We have to find the solution of given equations.

Multiplying by both sides of eq(1) by 2, we have

2(3x-3y) = 2(6)

6x-6y = 12 eq(3)

Subtracting eq(3) to eq(2) , we have

6x-6y -(6x-7y) = 12-8

6x-6y-6x+7y = 4

Adding like terms, we have

6x-6x+7y-6y = 4

y = 4

Putting the value of y in eq(1), we have

3x-3(4) = 6

3x-12 = 6

Adding 12 to both sides of above equation, we have

3x-12+12= 6+12

3x = 18

Dividing by 3 to both sides of above equation , we have

3x/3 = 18/3

x = 6

Hence, the solution set is (6,4).

User Abirami Bala
by
8.3k points
1 vote

Answer:

The correct option is d.

Explanation:

The given equations are


3x-3y=6 ....(1)


6x-7y=8 ..... (2)

Multiply equation (1) by by 2, to make same coefficient of x.


6x-6y=12 ....(3)

Subtract equation (2) form equation (3).


6x-6y-6x+7y=12-8


y=4

Substitute this value in equation (1),


3x-3(4)=6


3x-12=6


3x=18


x=6

The solution of the given system of equation is (6,4).

Therefore the correct option is d.

User Pravin Raj
by
7.7k points

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