Answer:
potential energy is maximum when streach distance of string is doubled
Step-by-step explanation:
we know that elastic potential energy of a spring is given as
..................(1)
here k is spring constant
and x is stretched distance of spring
if we double the spring constant then potential energy will be given as
![E_(1)=(1)/(2)* 2kx^2](https://img.qammunity.org/2020/formulas/physics/high-school/9qs6ltq0f9jw87j3s19r0l9gogdztv6eqx.png)
...............(2)
similarly if we double the stretch distance then potential energy in spring will be given as
![E_(2)=(1)/(2)* 4kx^2](https://img.qammunity.org/2020/formulas/physics/high-school/sa0sp9boannfo1whd9a69scplyyp3bk94s.png)
.............(3)
from equation 2 and equation 3 it is clear that
![E_(2)>E_(1)](https://img.qammunity.org/2020/formulas/physics/high-school/5wdvq6e34wsr1d8x1o1m4ymdze0kkq24dn.png)
it means potential energy is maximum when stretch distance of string is doubled