Question

What is the electric force between a glass ball that has +2.5 x 10^-6 C of charge and a rubber ball that has -5.0 x 10^-6 C of charge when they are separated by a distance of 0.0050 m?

Answer 1

As per Coulomb's law we know that force between two charges is given as

`F = (kq_1q_2)/(r^2)`

here we know that

`q_1 = 2.5 * 10^(-6) C`

`q_2 = -5.0 * 10^(-6) C`

`r = 0.0050 m`

now from above formula we will have

`F = ((9 * 10^9)(2.5 * 10^(-6))(5 * 10^(-6)))/((0.0050)^2)`

`F = 4500 N`

so they will attract towards each other as they are opposite in nature with force F = 4500 N