Question

A balloon rises vertically at the rate of 10 feet per second. It encounters a wind that gives a horizontal displacement of 5 feet per second. Find the angle its path makes with the horizontal.

Answer 1

63.44°

Step-by-step explanation:

We are given from the figure,

Vertical distance = 10 feet

Horizontal distance = 5 feet.

Trigonometric rule for the right triangles gives us,

`\tan x=(perpendicular)/(base)`

i.e.
`\tan x=(10)/(5)`

i.e.
`\tan x=2`

i.e.
`x=\arctan 2`

i.e. x= 63.44°

Hence, the angle made by the path with the horizontal is 63.44°