Question

On parallelogram PQRS below if P at (-1,6) and S is located at (-7,-3) what is the slope of QR

Answer 1

Explanation:

Given: PQRS is a parallelogram and the coordinates of P and S are (-1,6) and (-7,-3) respectively.

To find: The slope of QR.

Solution: The coordinates of P and S are (-1,6) and (-7,-3) respectively.

Then, Slope Of PS=
`(y_(2)-y_(1))/(x_(2)-x_(1))`

=
`(-3-6)/(-7+1)`

=
`(-9)/(-6)`

=
`(3)/(2)`

Thus, Slope of PS=
`(3)/(2)`.

Now, since it is given that PQRS is a parallelogram, thus Slope of PS will be equal to the slope of QR, thus slope of QR=
`(3)/(2)`.