Answer:
.
Reference angle is
![(\pi)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rupw15un64v2l679vp5ufrrgebx5fl65t5.png)
Explanation:
Given the value of x. we have to find the correct value of cosx.
![x=(2\pi)/(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/h1xxkrx8i62m8pr0ay1d6ldqaci1cn8xow.png)
Now, we have to find the exact value of
![cos{(2\pi)/(3)}](https://img.qammunity.org/2020/formulas/mathematics/high-school/rsoqqz97ehlhug8fsdrxq7hm4yxgffeqok.png)
![cos{(2\pi)/(3)}=cos((\pi)/(2)+(\pi)/(6))](https://img.qammunity.org/2020/formulas/mathematics/high-school/pwpb40asj5vslakhlvvezof1uwx3xlkw5f.png)
![=-sin((\pi)/(6))](https://img.qammunity.org/2020/formulas/mathematics/high-school/xise4hbwcj0t6hl3i5ufi3lhme9hk3v1e9.png)
![=-(1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h2srvr03rkick6387xrn8jleb01mg2ss17.png)
Now, we have to find the reference angle of
.
Since the angle
lies in second quadrant, the reference angle formula is
Reference angle=
.
=
![\pi-(2\pi)/(3)=(\pi)/(3)](https://img.qammunity.org/2020/formulas/mathematics/high-school/wdbkr0lhy2s6kp1csvr3mna03sroh9qsw8.png)