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If each term of an arithmetic sequence is multiplied by a fixed​ number, will the resulting sequence always be an arithmetic​ sequence?

2 Answers

2 votes

Answer:

yes correct, also when you are adding or subtracting

Explanation:

User AndyG
by
7.4k points
2 votes

Answer:

Yes, the resulting sequence will always be an arithmetic sequence.

Explanation:

We know that any arithmetic sequence is a sequence in which each term of the sequence is increased by a fixed constant as compared to the preceding term of the sequence.

This fixed constant is known as common difference,

i.e.
d=a_n-a_(n-1)

where


a_n is the nth term of the sequence.

Now, when each term of an arithmetic sequence is multiplied by a fixed​ number let a'.

Let
a_n' is the nth term of the new sequence.

Then we have:


a_1'=a'a_1


a_2'=a'a_2


a_3'=a'a_3

and so on

Also,


a_(n)'-a_(n-1)'=a'a_n-a'a_(n-1)\\\\a_(n)'-a_(n-1)'=a'(a_n-a_(n-1))\\\\a_(n)'-a_(n-1)'=a'd

for each n.

Hence, the sequence will again be an arithmetic sequence.

( Since, the sequence again vary by a fixed constant )

User Wenzi
by
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