Answer:
probability that he scores a goal both times is
.
Explanation:
It is given that Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots.
Therefore, P(X)=0.63.
Thus, the probability of getting success in his shoots will be,
![P(X^(c))=1-P(X)=1-0.63=0.37](https://img.qammunity.org/2020/formulas/mathematics/middle-school/it79wxq8frdywstngro4h1fdstyh78uznj.png)
probability that he scores a goal both times is =
![P(X^c){*}P(X^c)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6ba52542fwfr5s4cf8kggprymcrg8agrrl.png)
=
![0.37{*}0.37](https://img.qammunity.org/2020/formulas/mathematics/middle-school/asle407mhbi0c9f320vm6hsc1xh031133w.png)
=
![0.137](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g3pnu7t97tinz84fw27zqze7rhcp3ddwhi.png)
=13.7%