Question

Solve 56-10x≥ 20 + 8x.
O A. x≥ 2
OB. x2-2
OC. x≤2
OD. x≤-2

Answer 1

`\bf{56-10x\geq 20+8x }`

Subtract 8x on both sides.

`\bf{56-10x-8x\geq 20 }`

Combine −10x and −8x to get −18x.

`\bf{56-18x\geq 20 }`

Subtract 56 from both sides.

`\bf{-18x\geq 20-56 }`

Subtract 56 from 20 to get −36.

`\bf{-18x\geq -36 }`

Divide both sides by −18. Since −18 is <0, the inequality direction is changed.

`\bf{x\leq (-36)/(-18) }`

Divide −36 by −18 to get 2.

`\bf{x\leq 2 \ \ \to \ \ \ Answer}`

We conclude that the correct option is "C".

{ Pisces04 }

Answer 2

`\huge\boxed{\sf x\leq 2}`

Explanation:

Given inequality:

`56-10x\geq 20+8x\\\\Subtract \ 20 \ from \ both \ sides\\\\56-20-10x\geq 8x\\\\36-10x\geq 8x\\\\Add \ 10x \ to \ both \ sides\\\\36\geq 8x+10x\\\\36\geq 18x\\\\Divide \ 18 \ to \ both \ sides\\\\2 \geq x\\\\OR\\\\x\leq 2\\\\\rule[225]{225}{2}`