44.1k views
1 vote
Given the Vertices of ΔABC are A (2, -5,) B (-4, 6) and C (3, 1), find the vertices following each of the transformations FROM THE ORIGINAL vertices :

(I honestly have no idea what to do and I really need help with this one)

Given the Vertices of ΔABC are A (2, -5,) B (-4, 6) and C (3, 1), find the vertices-example-1
User Akazuko
by
7.8k points

1 Answer

2 votes

Answer:

I. A' = (5,-5), B' = (-1,6), C' = (6,1)

II. A' = (5,-11), B' = (-1,0), C' = (6,-5)

III. A' = (-5,-2), B = (6,4), C' = (1,-3)

Explanation:

We are given the vertices of ΔABC as A = (2,-5), B = (-4,6) and C = (3,1).

I. It is required to 'reflect the triangle about the line x= 3'.

This rule changes (x,y) to (x+3,y).

So, the new vertices are given by,

A' = (2+3,-5) = (5,-5)

B' = (-4+3,6) = (-1,6)

C' = (3+3,1) = (6,1)

II. It is required to 'translate the triangle 3 units to the right and 6 units down'.

This rule changes (x,y) to (x+3,y-6).

So, the new vertices are given by,

A' = (2+3,-5-6) = (5,-11)

B' = (-4+3,6-6) = (-1,0)

C' = (3+3,1-6) = (6,-5)

III. It is required to 'rotate the triangle by 90° about the origin counter-clockwise'.

This rule changes (x,y) to (y,-x).

So, the new vertices are given by,

A = (2,-5) implies A' = (-5,-2)

B = (-4,6) implies B = (6,4)

C = (3,1) implies C' = (1,-3)

User Bivin Vinod
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories