Answer:
g(x) rises more steeply than f(x)
Explanation:
Given:
![f(x)=√(16x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/taz94nc0cb6129ogfgxzrr2uzbd207bxaq.png)
![g(x)=16√(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/al63fu6vxyx21dq62crt66w8nuz5wa6a69.png)
The parent function of both f(x) and g(x) is same.
![\text{Parent function }:p(x)=√(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xk903scdi3t4ghirabxytgni3zdtl4qk7o.png)
![f(x)=√(16x)=4√(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nvzl196svqzkc5551ckan8ob53urff05m1.png)
![g(x)=16√(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/al63fu6vxyx21dq62crt66w8nuz5wa6a69.png)
The rise of function depends on the value of a.
Higher the value of a rises more because coefficient is more.
![p(x)=√(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mrplkd3o3zybi5kdyl1c4ovzocyuokn7gb.png)
![f(x)=4√(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/getrp0wm5o6ze0stgkqu4gi5dn1ps92ldt.png)
![g(x)=16√(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/al63fu6vxyx21dq62crt66w8nuz5wa6a69.png)
The coefficient of g(x) is more than f(x).
We can see graphically also. Please see attachment for graph.
Hence, g(x) rises more steeply than f(x).