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3 votes
G(x)=2(x−3) 2 −8
what is the vertex of the function?

2 Answers

5 votes


\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ g(x)=2(x-\stackrel{h}{3})^2\stackrel{k}{-8}~\hspace{10em}\stackrel{vertex}{(3,-8)}

User Loicfavory
by
8.4k points
2 votes

Answer:

(3,-8)

Explanation:

The parabola given in the form

y =a(x-h)^2 +k

where (h,k) is the vertex of the function

y =2(x−3)^ 2 −8

So (3, -8) is the vertex of the function

User Anupheaus
by
9.2k points

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