2 Answers

Krishna Shanbhag · Answer 1 · 2020-04-20T14:20:13+0000

Answer:
(2)/(35)

Explanation:

Given: The total number of ways of to choose 3 contestants out of 7 (including me and my friend)=35..................> Total outcomes.

Favorable outcomes = 2

Then the probability that me and my friend are both chosen =
$\frac{\text{favorable outcomes }}{\text{Total outcomes}}$

Thus , the probability that me and my friend are both chosen =
(2)/(35)

Zundi · Answer 2 · 2020-04-24T23:01:19+0000

Answer:

Option: A is the correct answer.

The probability that you and your friend both are chosen is:

A.
(5)/(35)

There are a total of 7 people and out of which 3 are to be selected.

Total possible ways of choosing three people are: 35

Also, now if you and your friend are chosen then there are 5 people left and now only one person is to be chosen out of these 5 people.

Hence, the probability is calculated as:

$(5_C_1)/(35)\\\\\\=((5!)/((5-1)!* 1!))/(35)\\\\\\=((5* 4!)/(4!))/(35)\\\\\\=(5)/(35)$

Hence, the answer is:

Option: A