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1 vote
Y=2(3)²
y=2/3x -4

solve this system of equations

User Yclkvnc
by
7.5k points

1 Answer

4 votes

Answer:

(33,-260)

Explanation:

y=2(3)².....equation(1)

y=2/3x -4 ...equation(2)

put equation(1) to equation(2)

2(3)² = 2/3x - 4

2(9)= 2/3x - 4

18 = 2/3x - 4

add 4 to both sides

18+4 = 2/3 x- 4 +4

22 = 2/3x

multiply via by 3

22×3 = 2/3x × 3

66 = 2x

divide both sides by 2

66/2 = 2x/2

33 = x

x=33

solve for y

to solve for y, put x in equation (2)

y=2/3x - 4

y = 2/3(33) - 4

y = 2/66 - 4

find the LCM of 66 and 1

the LCM is 66

multiply by their LCM

y = (2/66)66-4×66

y = 2 - 264

y = -260

solution= (33,-260)


User Hong Tang
by
7.5k points

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