Answer:
A (n+1, n+1, n-1, n-1)
Step-by-step explanation:
This disorder in chromosomal number is referred to as ANEUPLOIDY. Aneuploidy is a condition whereby one or more chromosomes are present in extra copies or deficient in number, but definitely not in a complete set i.e. neither diploid nor haploid. Aneuploidy, which is when an abnormal number of chromosomes occur in a cell, is caused by meiotic nondisjunction i.e. failure of chromosomes to separate during meiosis.
Nondisjunction occurs when pairs of homologous chromosomes fail to separate during meiosis I or sister chromatids fail to separate during meiosis II. The occurrence of nondisjunction in meiosis I or II leads to different results in the daughter cells/gametes.
Since meiosis I is being considered in this question, if homologous chromosomes fail to separate during the anaphase of meiosis I, the result is two gametes that lack particular gametes (n-1) and two gametes with an extra copy of the chromosome (n+1)
That is, after cytokinesis, the four gametes will have a chromosomal number of n+1, n+1, n-1, n-1.
N.B: The number of chromosomes in a normal gamete is haploid (n).
This case of aneuploidy can lead to lethal cases. If a normal gamete (n) is fertilized by the gamete with an extra copy of chromosome (n+1), the resulting zygote will possess a condition called TRISOMY, also, when the normal gamete (n) fuses with a gamete with no copy of the chromosome (n-1), the resulting zygote will have a monosomy condition.