Question

Please explain how to solve this equation for x: 456=x²+26x

Answer 1

You need to complete the square.

(b-/2(a))^2

(-26/2(1))^2 = 169

add to both sides

x^2+26x+169 = 456 + 169

now add everything together and cut b in half and place the exponent outside..

(x+13)^2 = 625

now find the a sqaure root of 625 and drop the parenthesis on the other side ..

x+ 13 = +/- 25

this means plus or minus 25...minus 13 from each side...

x= -13 +/- 25

now solve both equations to get the min and max x...

-13 -25 = -38

-13 + 25 = 12

x= -38 and x= 12

Answer 2

(x-12) (x+38)

Explanation:

Subtract 456 to the other side:

1) x²+26x-456

Factor:

2) (x-12) (x+38)

Hope this helps again!! :D