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How many liters of water vapor are in 36.21 g?

User VBA Pete
by
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1 Answer

6 votes

Answer:

45.02 L.

Explanation:

  • Firstly, we need to calculate the no. of moles of water vapor.
  • n = mass / molar mass = (36.21 g) / (18.0 g/mol) = 2.01 mol.
  • We can calculate the volume of knowing that 1.0 mole of a gas at STP occupies 22.4 L.

Using cross multiplication:

1.0 mole of CO occupies → 22.4 L.

2.01 mole of CO occupies → ??? L.

∴ The volume of water vapor in 36.21 g = (22.4 L)(2.01 mole) / (1.0 mole) = 45.02 L.

User Kavko
by
6.0k points